Download Höhere Analysis mit DERIVE: Mit zahlreichen Abbildungen, by Wolfram Koepf PDF

By Wolfram Koepf

Dr. habil. Wolfram Koepf forscht im Bereich der Computeralgebra am Konrad-Zuse-Zentrum für Informationstechnik, Berlin. Er ist Mitautor des Buches "Mathematik mit DERIVE" (Vieweg 1993).

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Extra info for Höhere Analysis mit DERIVE: Mit zahlreichen Abbildungen, Beispielen und übungsaufgaben sowie Mustersitzungen mit DERIVE

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248). Entsprechendes gilt fUr die anderen partiellen Ableitungen. 0 2 Mehrdimensionale Differentiation 48 Wie im Eindimensionalen gibt es Faile mit gradf(a:) = 0, wo trotzdem kein Extremum vorliegt, z. B. bei der Funktion f(x, y) = x yam Ursprung, s. 4. 4 Die Funktion f(x,y) = xy am Ursprung Um hinreichende Kriterien fiir lokale Extrema formulieren zu konnen, beschaftigen wir uns nun etwas genauer mit quadratischen Formen. 7 (Quadratische Form, Definitheit) Ist A = (ajk)nn eine symmetrische quadratische Matrix, so nennt man die Funktion QA : R,n - t R, mit n QA(a:):=a:TAx= L ajkXjXk j,k=l die von A erzeugte quadratische Form.

Xk, ~k+1' ... , ~n) - geXl, ... , Xk-l, ~k, ... , ~n)1 k=l n :5 L ~k I ~ :5 c Ix - el IXk - k=l fUr x E Bee, b). ' ee) = grad fee). 2 sofort die folgende Konsequenz. 2 Jede in einer offenen Teilmenge D C R n stetig partiell differenzier0 bare Funktion f : D -+ R m ist dort stetig. Auf Grund des Satzes werden wir in Zukunft statt ,,(n-mal) stetig partiell differenzierbar" nur noch ,,(n-mal) stetig differenzierbar" sagen. Zusammenfassend haben wir also die die folgenden Implikationen: 1. stetige partielle Differenzierbarkeit ==?

H(t) =g(cost,smt)= cos 2 t - sin 2 t 2 . 2 . 2 =cos t-sm 2 t=cos(2t) cos t+sm t erhalten. Natiirlich konnen wir mit dieser Darstellung sofort die Ableitung von h h'(t) = -2 sin (2t) bestimmen. Wir berechnen diese Ableitung nun mit Hilfe der Kettenregel. ,(t) = ( -sint ) cost sowie 38 2 Mehrdimensionale Differentiation , ( 4 X y2 4 x2Y ) 9 (x, y) = grad(x, y) = (x 2 + y2)2' - (x 2 + y2)2 erhalten wir h' (t) g' (j(t» = I' (t) = grad g( cos t, sin t) . ( ~~~~ t ) (4 cos t sin 2 t)( - sin t) + (-4cos2 t sin t)(cos t) -4 cos t sin t = -2 sin (2t) .

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